72x^2-145x+72=0

Solution for 72x^2-145x+72=0 equation:

72x^2-145x+72=0

a = 72; b = -145; c = +72;
Δ = b2-4ac
Δ = -1452-4·72·72
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-145)-17}{2*72}=\frac{128}{144}
=8/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-145)+17}{2*72}=\frac{162}{144}
=1+1/8
$